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Author Topic: the art of electronics : switching the high side of a load  (Read 662 times)

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Offline CamelkosTopic starter

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the art of electronics : switching the high side of a load
« on: June 01, 2020, 04:26:54 pm »
hi everybody,
i'm reading the art of electronics 2 and i'm stuck at the circuit B to switch the high side of a load returned to ground in the chapter of bipolar transistors,
can someone explain it to me please, thank you all !!
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Offline bob91343

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Re: the art of electronics : switching the high side of a load
« Reply #1 on: June 01, 2020, 08:59:44 pm »
We don't all have that book so give us the source and perhaps we can help.
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Online MarkF

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Re: the art of electronics : switching the high side of a load
« Reply #2 on: June 01, 2020, 09:25:48 pm »
Is this the circuit?

999164-0

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Offline bob91343

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Re: the art of electronics : switching the high side of a load
« Reply #3 on: June 02, 2020, 04:06:56 pm »
If B is the circuit, then driving Q2 with a pulse will turn it on, which in turn provides base current for Q3 and thus energizing the load.
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Online MarkF

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Re: the art of electronics : switching the high side of a load
« Reply #4 on: June 02, 2020, 07:33:54 pm »
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