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| "Veritasium" (YT) - "The Big Misconception About Electricity" ? |
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| rfeecs:
--- Quote from: SilverSolder on January 21, 2022, 08:32:54 pm ---I have a quick question, maybe someone can help me understand: What happens if we put the bulb inside a steel Faraday cage? That would mean an outside electrical field cannot reach it, and any magnetic field would not reach the bulb either (it would by-pass the bulb via the steel box). --- End quote --- How would the wires get from the outside to the inside of the Faraday cage? |
| SilverSolder:
--- Quote from: rfeecs on January 21, 2022, 08:45:53 pm --- --- Quote from: SilverSolder on January 21, 2022, 08:32:54 pm ---I have a quick question, maybe someone can help me understand: What happens if we put the bulb inside a steel Faraday cage? That would mean an outside electrical field cannot reach it, and any magnetic field would not reach the bulb either (it would by-pass the bulb via the steel box). --- End quote --- How would the wires get from the outside to the inside of the Faraday cage? --- End quote --- 0.01mm holes drilled through the 5cm thick steel box for a thin, insulated wire. Drilled from two sides at an angle, so there is no direct flux path through. |
| rfeecs:
The energy would pass through the insulation around the wires. |
| HuronKing:
What if an infinite conducting sheet is placed between the source and load? It's the same thing as Silversolder's question and it is answered in Kraus' Electromagnetism, Chapter 10. You've built a waveguide: https://physics.stackexchange.com/questions/435041/poyntings-vector-and-its-application-to-circuits And this is one of the biggest problems in designing waveguides. How do you get the signal into the waveguide without reflection or radiation at the connection point? Impedance matching. |
| SilverSolder:
The wires are very thin, 0.01mm, just enough to light a small bulb. The insulation is the thinnest possible layer of vacuum that you can have without flashing over (a few micrometers), and the box is at least 500mm thick. I am struggling to understand how the fields will be able to carry energy to the bulb. And if they do make it in... wouldn't the tortuous path they have to take to get there mean there would be more resistance, compared to a layout that does not impede the fields in any way? |
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