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| Veritasium "How Electricity Actually Works" |
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| T3sl4co1l:
Do you have a setup I can test? |
| electrodacus:
--- Quote from: T3sl4co1l on May 03, 2022, 06:30:11 pm ---Do you have a setup I can test? --- End quote --- What is exactly that you want to test ? Is that moving energy from one charged capacitor to an identical discharged capacitor using a DC-DC converter will result in final voltage being significantly more than 1/2 and close to 0.707 ? If you think that is not true then you are basically saying that capacitor energy equation is wrong. E = 0.5 * C * V2 I already made the example with Vi = 3V and C = 1F Initial energy in charged capacitor is 0.5 * 1F * 3V2 = 4.5Ws If energy is conserved after the switch was closed and you basically have a 2F capacitor (two 1F in parallel). 0.5 * 2F * (3V * 0.707)2 = 4.5Ws |
| aetherist:
--- Quote from: electrodacus on May 03, 2022, 03:50:46 am --- --- End quote --- Two capacitors cant exist like this. This circuit needs 2 switches, not 1 switch. |
| electrodacus:
--- Quote from: aetherist on May 03, 2022, 08:27:47 pm --- Two capacitors cant exist like this. This circuit needs 2 switches, not 1 switch. --- End quote --- :) what? Why will you need a second switch ? redundancy :) |
| SiliconWizard:
If you assume the bottom 'wire' between the two capacitors has zero impedance, then it's essentially just one capacitor. Isn't it? |
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