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Veritasium "How Electricity Actually Works"

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T3sl4co1l:
Do you have a setup I can test?

electrodacus:

--- Quote from: T3sl4co1l on May 03, 2022, 06:30:11 pm ---Do you have a setup I can test?

--- End quote ---

What is exactly that you want to test ?
Is that moving energy from one charged capacitor to an identical discharged capacitor using a DC-DC converter will result in final voltage being significantly more than 1/2 and close to 0.707 ?

If you think that is not true then you are basically saying that capacitor energy equation is wrong.
E = 0.5 * C * V2

I already made the example with Vi = 3V and C = 1F
Initial energy in charged capacitor is
0.5 * 1F * 3V2 = 4.5Ws

If energy is conserved after the switch was closed and you basically have a 2F capacitor (two 1F in parallel).
0.5 * 2F * (3V * 0.707)2 = 4.5Ws

aetherist:

--- Quote from: electrodacus on May 03, 2022, 03:50:46 am ---
--- End quote ---
Two capacitors cant exist like this. This circuit needs 2 switches, not 1 switch.

electrodacus:

--- Quote from: aetherist on May 03, 2022, 08:27:47 pm ---
Two capacitors cant exist like this. This circuit needs 2 switches, not 1 switch.

--- End quote ---

:) what?
Why will you need a second switch ? redundancy :)

SiliconWizard:
If you assume the bottom 'wire' between the two capacitors has zero impedance, then it's essentially just one capacitor. Isn't it?

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