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| Veritasium "How Electricity Actually Works" |
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| vad:
--- Quote from: Naej on May 11, 2022, 08:55:27 pm --- First show your solution for a circuit which extract 1% of the energy travelling in the vacuum in the diagram. --- End quote --- Create vacuum in the box and heat the outer wire (cathode) high enough so sufficient number of electrons will flow towards the inner wire (anode) to tap the 1% of energy. They call this a diode vacuum tube, don’t they? Now is your turn. |
| hamster_nz:
--- Quote from: vad on May 11, 2022, 09:09:54 pm --- --- Quote from: Naej on May 11, 2022, 08:55:27 pm --- First show your solution for a circuit which extract 1% of the energy travelling in the vacuum in the diagram. --- End quote --- Create vacuum in the box and heat the outer wire (cathode) high enough so sufficient number of electrons will flow towards the inner wire (anode) to tap the 1% of energy. They call this a diode vacuum tube, don’t they? Now is your turn. --- End quote --- That was along the lines of what I was thinking... |
| PlainName:
--- Quote from: electrodacus on May 11, 2022, 03:46:06 pm --- --- Quote from: dunkemhigh on May 11, 2022, 03:37:13 pm --- --- Quote from: electrodacus ---you will see that the conductor heats uniformly on the entire conductor cross section --- End quote --- Easy for you to say. How about you demonstrate that? --- End quote --- People tested that well before I was born it just seems that internet instead of being this great learning tool it becomes a space for misinformation. What about you just measure the electrical resistance of a copper pipe with thin walls and the electrical resistance of a copper bar with same diameter then let me know if there is a difference. If there is a difference in resistance that means electrons from your multimeter traveled through the middle of the copper bar not just close to the surface. You will see that resistance will be proportional with the copper section area so electron wave will travel uniformly through the material. --- End quote --- Woah! No-one's talking resistance here (except you, as a diversion). You said "you will see that the conductor heats uniformly on the entire conductor cross section" - that is heat, thermal. I am wondering just how you can measure the internal temperature of a conductor, and you Internet isn't any help there. So, just how do you see that? If you make a hole and place a probe you're affecting the conductor integrity, and even with a thermal imager you're only going to see the outside. Or was this just another 'fact' or 'law' you made up on the spot? |
| electrodacus:
--- Quote from: vad on May 11, 2022, 08:17:55 pm --- --- Quote from: electrodacus on May 11, 2022, 07:21:41 pm --- That transient when you are closing the switch (with is what Derek concentrated on) is not DC. All that was needed and if you understood the graphs is exactly what Derek got as a result just wrongly explained the reason for that result. --- End quote --- I thought you were referring to DC when you wrote this: “ The difference is that with DC the energy flow is uniform inside the wire meaning the entire section of the wire is used while with AC the higher the frequency and line capacitance the more charges will flow closer to the surface forming the capacitor.” No matter DC, AC or transient analysis - you are using wrong tools. --- End quote --- That is exactly what I said in reply to Dave. I do not think I use the wrong tools as I do get the correct result and I want you to show me an alternative way to do it. |
| electrodacus:
--- Quote from: vad on May 11, 2022, 09:09:54 pm ---Create vacuum in the box and heat the outer wire (cathode) high enough so sufficient number of electrons will flow towards the inner wire (anode) to tap the 1% of energy. They call this a diode vacuum tube, don’t they? Now is your turn. --- End quote --- So you understand that energy transfer is done by the wave of electrons. How many electrons flow from the wire/copper pipe in Derek's experiment ? Should be very substantial and directional if you want to account for the energy transferred in the first 65ns. What about the rest ? |
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