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Veritasium "How Electricity Actually Works"
hamster_nz:
--- Quote from: electrodacus on May 12, 2022, 05:15:49 pm ---And you can get very close to that also by using a DC-DC converter to transfer energy from one capacitor to the other.
--- End quote ---
You keep saying this, and demanding "proof" from others, but you have yet to demonstrate this, even though you assert it over and over. Please demonstrate that this is at all possible.
I think you will find that because the capacitor is a low impedance load (it will store all the energy you can give it) the transfer from the DC-DC convertor will be limited by the convertor's input and output impedance. When the voltages in the capacitors are equal you will end up with less than 0.5 Vinitial in both.
PlainName:
--- Quote ---That's the goal, to play people like a fiddle and goad them in to making more and more responses.
--- End quote ---
I think he genuinely believes what he says (that he is correct and everyone else "doesn't understand properly"). And much of the arguments are merely ways to not have to accept that he is wrong.
--- Quote ---The best solution is to simply ignore the posts and decline to respond. Electrodacus will eventually get bored and go away.
--- End quote ---
If other topics are any guide, that would only be temporary until he starts up a new thread to demonstrate that, actually, he was right all along. Looks like a troll but I am not convinced.
What did turn off the lights on the faster than the wind thing was making him see he hadn't got a leg to stand on. That shut him up about it, until now (when it is far enough back that he can pretend he missed the end and insist energy storage is the answer to everything, as any fule would kno).
electrodacus:
--- Quote from: hamster_nz on May 12, 2022, 09:01:55 pm ---
--- Quote from: electrodacus on May 12, 2022, 05:15:49 pm ---And you can get very close to that also by using a DC-DC converter to transfer energy from one capacitor to the other.
--- End quote ---
You keep saying this, and demanding "proof" from others, but you have yet to demonstrate this, even though you assert it over and over. Please demonstrate that this is at all possible.
I think you will find that because the capacitor is a low impedance load (it will store all the energy you can give it) the transfer from the DC-DC convertor will be limited by the convertor's input and output impedance. When the voltages in the capacitors are equal you will end up with less than 0.5 Vinitial in both.
--- End quote ---
I will not even bother to answer your comments as it will be a never ending story. You clearly lack basic understanding.
What is your prediction if you are using say a 80% efficient DC-DC converter with constant current limiting with current limited so that wires and capacitor internal resistance is basically insignificant in therms of extra losses or say the 80% efficiency includes those losses to make the calculation simpler.
What will be the end voltage if you transfer from a charge 1F capacitor 3V to a identical 1F capacitor that is fully discharged so 0V
Unless you can offer a prediction you can not claim you understand how any of this works. And feel free to use any tool you want to come up with the answer.
Also when I mentioned that end voltage will be higher than 1.5V some of you (not sure if you included) had concerned about the fact that a DC-DC converter uses active components. This will again be a lack of understanding if you or the ones that made this comment think extra energy will somehow magically appear in this isolated circuit because of the use of a DC-DC converter that is only powered by the charged capacitor.
electrodacus:
--- Quote from: IanB on May 12, 2022, 09:01:36 pm ---
But you really shouldn't try. Electrodacus has a habit of saying things that are clearly wrong, muddled or confusing, and then inviting people to argue about them. It's no surprise that threads like this one tend to go on and one without end. That's the goal, to play people like a fiddle and goad them in to making more and more responses. The best solution is to simply ignore the posts and decline to respond. Electrodacus will eventually get bored and go away.
"Don't feed the trolls"
--- End quote ---
You are welcome in providing the answer to the question I posted to hamster_nz. In fact anyone is welcome.
hamster_nz:
--- Quote from: electrodacus on May 12, 2022, 10:42:38 pm ---
--- Quote from: hamster_nz on May 12, 2022, 09:01:55 pm ---
--- Quote from: electrodacus on May 12, 2022, 05:15:49 pm ---And you can get very close to that also by using a DC-DC converter to transfer energy from one capacitor to the other.
--- End quote ---
You keep saying this, and demanding "proof" from others, but you have yet to demonstrate this, even though you assert it over and over. Please demonstrate that this is at all possible.
I think you will find that because the capacitor is a low impedance load (it will store all the energy you can give it) the transfer from the DC-DC convertor will be limited by the convertor's input and output impedance. When the voltages in the capacitors are equal you will end up with less than 0.5 Vinitial in both.
--- End quote ---
I will not even bother to answer your comments as it will be a never ending story. You clearly lack basic understanding.
What is your prediction if you are using say a 80% efficient DC-DC converter with constant current limiting with current limited so that wires and capacitor internal resistance is basically insignificant in therms of extra losses or say the 80% efficiency includes those losses to make the calculation simpler.
What will be the end voltage if you transfer from a charge 1F capacitor 3V to a identical 1F capacitor that is fully discharged so 0V
Unless you can offer a prediction you can not claim you understand how any of this works.
--- End quote ---
What part of "When the voltages in the capacitors are equal you will end up with less than 0.5 Vinitial in both." is not "offering a prediction"?
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