General > General Technical Chat
Veritasium "How Electricity Actually Works"
electrodacus:
--- Quote from: hamster_nz on May 16, 2022, 08:35:51 pm ---We are going back to where we were in reply #266
electrodacus will say that the lamp (or in this case LEDs) are lit, but power doesn't flow through the capacitors, only in and out at the same time :-//
--- End quote ---
Not "in and out" just in and when capacitors are charged no current will flow other than for the small leakage depending on the quality of those capacitors.
PlainName:
Er, hate to point this out but in the simplified circuit it goes: supply -> capacitor -> resistor -> return.
Now, the cap is not charged. It is 0V both sides. Connect the supply and now there is a voltage across the resistor. Where did that come from if not through the capacitor?
electrodacus:
--- Quote from: dunkemhigh on May 16, 2022, 08:48:27 pm ---Er, hate to point this out but in the simplified circuit it goes: supply -> capacitor -> resistor -> return.
Now, the cap is not charged. It is 0V both sides. Connect the supply and now there is a voltage across the resistor. Where did that come from if not through the capacitor?
--- End quote ---
In to capacitor not through capacitor.
You can not have a current "through" the dielectric.
You understand that when the capacitor is full may be 30ns or 30s but once the capacitor is fully charged (and I mean charged so it stores energy) current flow will stop. And current flows through wires but in to capacitor not through it.
hamster_nz:
--- Quote from: electrodacus on May 16, 2022, 09:03:14 pm ---
--- Quote from: dunkemhigh on May 16, 2022, 08:48:27 pm ---Er, hate to point this out but in the simplified circuit it goes: supply -> capacitor -> resistor -> return.
Now, the cap is not charged. It is 0V both sides. Connect the supply and now there is a voltage across the resistor. Where did that come from if not through the capacitor?
--- End quote ---
You can not have a current "through" the dielectric.
--- End quote ---
Demonstrations such as placing an ammeter on both legs of a capacitor as it charges, showing the same current flowing both terminals, at the same time are complete fabrications...
Unless it has to be the same electron flowing out as flowed in - in which case long wires are out due to the slow drift velocity. On a 1m x 2mm diameter copper wire, carrying 1A DC , it will take on average about 12 hours for an electron to travel down that wire.
PlainName:
Something goes through to use up energy across that resistor (or lamp, or anything else that consumes power). Where does it come from? It is energy of some form, isn't it?
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