General > General Technical Chat
Veritasium "How Electricity Actually Works"
SandyCox:
--- Quote from: electrodacus on May 18, 2022, 01:18:00 am ---Electrical power is product of electrical current and electrical potential. I think is clear that you can not have electric current flow through air at least not with 20V and 1m of distance so there can not be any power.
--- End quote ---
What happens when the electric field isn't conservative? Does current always involve electrons?
electrodacus:
--- Quote from: dunkemhigh on May 18, 2022, 08:04:05 am ---
--- Quote ---I explained that electrons from the plate of once capacitor will be pushed in the other capacitor plate
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Across 1m of air? What is it that the plus side can cause the negative side to rise to the same voltage and put out some current?
--- End quote ---
No electrons and thus no energy will travel that 1m gap.
When you have two capacitors in series connected to a supply each capacitor will have a plate connected to supply one to the positive and the other to the negative terminal of the supply.
Those plates will act as if it was a single capacitor then the other two plates that are connected with a wire between them will always have the same number of electrons when discharged and when charged is just that when charged electrons from one plate travels through the wire to the other plate as capacitors are charged.
If you have a lamp there in series there will just be extra energy wasted as capacitors charge since is like wire has higher resistance to electron flow.
Seen from the outside as a black box with just two wires the two capacitors in series will look like a single capacitor with lower capacity.
There is no difference between one capacitor or two or 3 capacitors in series.
From outside you will see that the amount of energy going in to black box will be equal with the amount going out plus the energy lost as heat on the DC ESR and the DC ESR includes the wire connecting the two capacitors in series inside the black box. If you add a lamp in that black box that will just further contribute to increase in the DC ESR and you will not be able to know form the outside that there is a lamp in the box or if there are two capacitors in series or just one.
You will not be able to know that from outside of the black box because no matter what measurements you make there will be no difference from a single capacitor or multiple in series and or lamps or resistors added to that in series.
electrodacus:
--- Quote from: SandyCox on May 18, 2022, 09:32:40 am ---
What happens when the electric field isn't conservative? Does current always involve electrons?
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In an isolated system the field will be conservative. Electric current will always require some sort of charged particle either electrons or ions. In a wire the electrons will be the ones that move. In a battery the ions will move from one plate to another.
So to transport electrical energy from one plate to another you need electron flow usually in a wire but with very high voltages the electrons can also travel through air but not the case here with 20V and 1m of air.
So electric and magnetic field are conservative in Derek's experiment.
PlainName:
--- Quote ---No electrons and thus no energy will travel that 1m gap.
When you have two capacitors in series connected to a supply each capacitor will
--- End quote ---
Hey, please try not to introduce dead cats. Just stick with the ultra-simple circuit we were discussing: PSU->cap->res->return.
So, if no energy is passed from one side to the other, what is the resistor burning?
Hang on... O. M. G.... Maybe you are converting to aetherwind?
Joking aside, explain how the resistor can show a voltage across it and sink some current. Where is that coming from?
snarkysparky:
""Electric current will always require some sort of charged particle either electrons or ions""
Yes but the charged particles need not "transfer" to transmit energy.
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