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Veritasium "How Electricity Actually Works"

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electrodacus:

--- Quote from: hamster_nz on May 19, 2022, 02:36:51 am ---Why do you keep bringing up superconductors?  :-//

What's wrong with copper?

--- End quote ---

??? You did that when you mentioned a wire with zero resistance.

hamster_nz:

--- Quote from: electrodacus on May 19, 2022, 03:15:03 am ---
--- Quote from: hamster_nz on May 19, 2022, 02:36:51 am ---Why do you keep bringing up superconductors?  :-//

What's wrong with copper?

--- End quote ---

??? You did that when you mentioned a wire with zero resistance.

--- End quote ---
Well let's pick 1m of 2mm copper wire.  That's about about 0.005 ohms.

By your math...


--- Quote from: electrodacus on May 18, 2022, 11:04:31 pm ---...and since electron flow is electrical current and electrical current multiplied with voltage is power and power integrated over time is energy it means energy flows only in wire.

--- End quote ---

"electrical current multiplied with voltage is power" - 1A at 0.005V is 0.005 W

" and power integrated over time is energy" - let's integrate 1W for a second.... it's 0.005 J.

So for a 1A in that 1m of 2mm copper wire (a voltage drop of 0.005V), your math calculates that only 0.005 J of energy flowed in that wire during that second.

electrodacus:

--- Quote from: hamster_nz on May 19, 2022, 03:41:28 am ---
Well let's pick 1m of 2mm copper wire.  That's about about 0.005 ohms.

By your math...



"electrical current multiplied with voltage is power" - 1A at 0.005V is 0.005 W

" and power integrated over time is energy" - let's integrate 1W for a second.... it's 0.005 J.

So for a 1A in that 1m of 2mm copper wire (a voltage drop of 0.005V), your math calculates that only 0.005 J of energy flowed in that wire during that second.

--- End quote ---

So ? Do you see any problems with that ?
Yes one meter of wire with just 5mOhm resistance will have a voltage drop of just 5mV at 1A.
That 5mJ is the energy that got lost as heat in that wire.
Assuming you had 5V supply the entire circuit should have had 5Ohm for 1A to flow through it so that 1m of wire is just a part of the total circuit.

SandyCox:

--- Quote from: electrodacus on May 19, 2022, 12:55:28 am ---
--- Quote from: dunkemhigh on May 19, 2022, 12:47:36 am ---
Just one more time: is there or is there not an air gap between the energy source and the energy consumer?

That is the question I am asking. I am not asking the question you would prefer to think I should ask, I am asking this specific and very simple one.[

--- End quote ---
Now you answer this simple question. Is there any electric current passing through this gap ?
If you say no then you also say no to there is no energy delivered through that gap and all energy travels in wire.

--- End quote ---
So what is you answer? Yes or No?

Are you sure you're an Engineer and not a Politician?

SandyCox:

--- Quote from: electrodacus on May 18, 2022, 03:50:35 pm ---
--- Quote from: SandyCox on May 18, 2022, 09:32:40 am ---
What happens when the electric field isn't conservative? Does current always involve electrons?

--- End quote ---

In an isolated system the field will be conservative. Electric current will always require some sort of charged particle either electrons or ions. In a wire the electrons will be the ones that move. In a battery the ions will move from one plate to another.

So to transport electrical energy from one plate to another you need electron flow usually in a wire but with very high voltages the electrons can also travel through air but not the case here with 20V and 1m of air.

So electric and magnetic field are conservative in Derek's experiment.

--- End quote ---
Wrong and wrong. Do you even know what a conservative field is? Have you heard of displacement current?

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