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Veritasium "How Electricity Actually Works"
hamster_nz:
--- Quote from: electrodacus on May 20, 2022, 03:12:23 am ---
--- Quote from: hamster_nz on May 20, 2022, 03:10:20 am ---The battery. Those electrons didn't just get into the capacitors by themselves now did they?
--- End quote ---
Losing half the energy as heat is not enough ? You can say they went downhill.
--- End quote ---
Oh, on second read your question it makes no sense.... I missed the extra "did" on the end.
electrodacus:
--- Quote from: hamster_nz on May 20, 2022, 04:17:46 am ---
Oh, on second read your question it makes no sense.... I missed the extra "did" on the end.
--- End quote ---
What question are you referring to?
Storing 72mJ in the capacitor resulted in 72mJ lost as heat so you can say charge efficiency is 50%
This charge efficiency can be improved to at least 90% if if you add as a minimum an inductor and diode as demonstrated in the past.
Also that 50% loss can be converted to something other than heat like maybe visible light by adding a lamp in series (just one example of many posible).
electrodacus:
--- Quote from: IanB on May 20, 2022, 03:26:03 am ---
It's fascinating seeing how many different ways he can come up with to argue that black is white, but yes, it does get boring after a while.
--- End quote ---
You are making the black white.
Energy stored is just that and not work.
Claiming a charged capacitor has no stored energy is just absurd.
IanB:
--- Quote from: electrodacus on May 20, 2022, 04:30:46 am ---Claiming a charged capacitor has no stored energy is just absurd.
--- End quote ---
Of course. That is why nobody has ever claimed that.
--- Quote ---Energy stored is just that and not work.
--- End quote ---
On the contrary, work is energy stored, heat is energy lost.
Here's a reference:
https://openstax.org/books/university-physics-volume-2/pages/8-3-energy-stored-in-a-capacitor
--- Quote ---To move an infinitesimal charge dq from the negative plate to the positive plate [of a capacitor] (from a lower to a higher potential), the amount of work dW that must be done on dq is dW=Vdq=(q/C)dq.
This work becomes the energy stored in the electrical field of the capacitor. In order to charge the capacitor to a charge Q, the total work required is...
--- End quote ---
Alex Eisenhut:
--- Quote from: electrodacus on May 20, 2022, 04:30:46 am ---
--- Quote from: IanB on May 20, 2022, 03:26:03 am ---
It's fascinating seeing how many different ways he can come up with to argue that black is white, but yes, it does get boring after a while.
--- End quote ---
You are making the black white.
Energy stored is just that and not work.
Claiming a charged capacitor has no stored energy is just absurd.
--- End quote ---
I don't think anyone claimed that.
Does a capacitor store time?
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