I've recently been trying to figure out a realistic way to design my traces on my 2 layer PCB (to be made by OSHPark) that can handle GNSS antenna signals (like from GPS satellites). According to the datasheet of BGA725L6 (a GNSS amplifier), it expects an inductor and a capacitor in series of 0402 size between the antenna patch and itself (the GNSS amplifier IC), which implies the trace width for a 50 ohm characteristic impedance would be around 20mil. However I used the calculators online for characteristic impedance for my PCB and instead I got 118mil for a 50 ohm characteristic impedance. Now this would mean I need 1812 components to reduce signal reflecting back caused by the changing trace width from trace to the pads of the passive components (lol V does not equal IR), however this is drastically larger than what the datasheet implies. I wouldn't even be able to avoid the massive trace width jump from the trace to the actual pad of the GNSS amplifier. I have a feeling I'm supposed to use a multilayer board with thinner copper and a thinner dielectric thickness (between layers), but is it even remotely possible to handle GNSS signals well on 2 layer FR4?
Additionally, the datasheet suggests the values of the capacitor and the inductor to be 1nF and 7.5nH, but that places the resonance frequency significantly outside of the 1.1 to 1.6 GHz range that GNSS (like GPS) signals uses. Luckily, the datasheet of the GNSS processing IC I'm using suggests those components to be 120pF and 5.6nH instead which has a resonance frequency right on the target, but both minimum impedances aren't the most optimised (14 ohms, but could be <10 ohms with a better cap inductor choice). Why does the datasheet say the inductor is necessary for impedance matching? Is it worth it going for a 3rd order filter to filter out white (gaussian?) noise better (as white noise is introduced for all frequencies unfiltered)?