Topic starter declared 10 ps jitter limit.
Yes. That's digital signal. It has rise and fall times. It might be around 500 ps (50 times longer than 10 ps). Whatever samples this digital signal (presumably ADC, but it doesn't really matter) detects the clock edge every time when the signal passes through a certain threshold.
If the overall voltage level of the signal varies, the transition curve moves up and down.
When voltage rises, the curve moves up, so it will pass through the threshold earlier and the ADC will detect the clock edge earlier.
When voltage falls, the curve moves down, so it will pass through the threshold later and ADC will detect the clock edge later.
This is the mechanism which creates jitter (and adds this jitter to the pre-exosting jitter). Thus, if you don't control voltage variations, the jitter will become worse. This is primarily the question of stability of power supply, correct bypassing, PCB design etc. The more parts you add into your chain, the harder it is to control voltage variations and the worse jitter you are going to get.
Another factor is temperature. If it varies, the propagation delays change. Although this is a very slow change, it too depends on the number of components on the way of the signal.
This is impossible to achieve with FPGA.
At least with popular Cyclone 4 or Spartan 6 you will get about 100-200 ps for better case.
I don't think it's possible with anything.
However, there's no reason why 74 series ICs should be any different than FPGAs - they're built on the same technology and there's no reason to believe they would have dramatically different characteristics.
Although you probably cannot achieve 10 ps, you can try to do the best you can. If you use more components, more PCB traces, more legs, more vias etc., you will get more jitter because each of these elements can only add jitter, but cannot remove it. Thus the key is to use less of everything - straight PCB traces, good bypassing, less components, less things that can add jitter. In this respect, FPGA wins because everything is compact and you already have your signal inside FPGA.