https://forums.intel.com/s/question/0D50P00003yyK4ASAU/max-10-jtag-voltage-question?language=frThis post pretty much sums up my questionning, I wonder
My setup/voltage from my board is like this, like on this jpeg: I have a terasic probe I intend to use, wich will be connected to my PC, the ribbon is about 7 inches long but I can get a shorter one. The distance from the FPGA pins to the header is about 20mm. Am I safe ? If not what circuit/part exactly I need to add to my board?
Here is a quote from the last post of that forum...
Quote: " Back to the basics. The schematic in post# 1 makes no sense, the relevant point for possible JTAG overshoot is the USB cable supply voltage, not the pull-up resistor voltage. You have JTAG connector pin 4 connected to 3.3V, this might, if at all, be causing overshoot problems with long JTAG traces. The suggestion in the MAX 10 Design Guidelines is to
power the USB cable with 2.5V ?? How ??, consequently the pull-up resistors will be connected to the same voltage.As previously stated, I won't provide an additional 2.5V supply in a single supply MAX 10 design (unless it's used for other purposes, e.g. LVDS IO). I prefer silicon or schottky clamp diodes for the JTAG port, e.g.
one of the popular 6-pin ESD protection diode networks." Have an example?? I hate it when people act all snarky like this.