Telecommunications systems use 0V and -48V to protect the integrity of the network from electrolytic corrosion. A buried wire at a positive potential with respect to ground will tend to thin and break, whereas a wire at negative potential won't.
A more "complete" explanation is that by making the buried wires negative with respect to ground, the electrolytic current loops travels from the Telco's grounding stake to the wires, and thus it's the Telco's grounding stake that gets thinned and corroded. Since it's absolutely massive to begin with (compared to the thin underground wires), it'll take decades to deteriorate to a problematic extent. Furthermore, if it does deteriorate, it's easy to find and fix.
A car has an electrical system which is isolated from earth, so that's not an issue.
Well, planet Earth is isolated and that doesn't prevent corrosion from happening in Telco wires on Earth
. If there was a break in a car's wire insulation, connected by rainwater to the body of the car, and then on to the negative terminal of the battery (as is typically done), then the wire will corrode and fail.
Alternatively, if the car's positive terminal was used as a grounding point (equivalently, the car uses -12V
with respect to car chassis), then the wire would be fine and it would be the nearby chassis of the car that gets corroded.
So I think this is very much an issue! I'd argue that if I had a break in a wire in my car, I would actually prefer for the wire to rapidly fail so that the problem can be fixed (replacing a wire in a car is ultra-trivial compared to buried telco cable!). A new wire costs much less that a replacement for a rusted-through car chassis!
Whether this was actually a deliberate decision by car-makers though, I have no idea.
None of this has anything to do with voltage drops or power transmission efficiency. The voltages and currents in a system consisting of a battery, load, wires and vehicle chassis, can all be easily calculated just by applying Kirchhoff's laws.
Agreed, of course.