Hi,
Would you agree that the relay J115F11C12VDCSH.9 has a datasheet which makes it impossible to make a PCB footprint for it?
I am speaking in relation to the position of the outer case in relation to the location of the drill holes.
In making a footprint as best i can, I am guessing that the case is , in any place, at least 4mm from the centre of the nearest drill hole to that point of the case, and then making the case conform to that (as attached)….is this a good conclusion? (ie, to avoid collision with neighbouring components on the PCB)
....then i just extended its width to be at least 26.9mm, to accord with the stated width......my initial width from the "method" was 25.8mm, so to be sure, i extended the width 1.1mm in each direction.
(my length was more than the stated 31.7mm when using the "method", so i left the length as it was.)
Would you agree with this?
J115F11C12VDCSH.9 Relay
https://www.citrelay.com/Catalog%20Pages/RelayCatalog/J115F1.pdf