..I'm not sure I understand the concepts of SAR ADC with these modes I'm afraid.
Thank you.
With those ADCs (SAR or SD) with 5V Vref and 5V Vcc, and 0V GND, the meaning of
input voltages of the ADC chip itself in the differential mode is as follows:
1. signal at A input could be from 0V (gnd) to 5V
2. signal at B input could be from 0V to 5V
3. in diff mode
input signals at A and B are (ideally) symmetrically mirrored around the "V_CM - Common Mode Voltage" which is 2.5V (the Middle of Vref)
4. therefore if talking -5V to +5V input range it means for example either A=0V and B=5V (the result is -5V), or A=5V and B=0V (the result is +5V), and that gives you "the ADC input range from -5V to +5V".
ADC_OUT = ( A - B ), full scale range ( Amax - Bmax ) = +/-Vref
The ADC will return the binary coded result which is formatted that way, thus you get the result from -5V to +5V.
So the moral is: you cannot feed into ADC's A or B input a signal larger than 5V and smaller than 0V (GND).If there is an AFE -> then it depends on the AFE's design/wiring, what could be
the input range into the AFE's inputs..
PS: there are couple of exceptions - so called "ADC chips with true bipolar inputs" where the voltage could be negative against GND and larger than Vcc, but the chip you work with (and most of the highend 24..32bitters) are limited to 0..Vcc (unipolar) physical input range as described above..
PPS: FYI - nice pictures with the A and B diff signals:
https://www.planetanalog.com/signal-chain-basics-120-designing-front-end-drivers-for-linear-performance-on-sar-adcs/