That's exactly what I would expect. Your current source has an output proportional to the differential of the voltage source, so the current output increases at 20dB/decade. Your simple integrator rolls off at 20db/decade above the pole formed by 1k/100n 1/(2*pi*1k*100n) = 1.5kHz. When combined this gives a flat response up to a few hundred kHz.
Above this the op-amp is running out of gain/bandwidth, the output impedance increases and so the voltage at the inverting pin passes through the 100n cap to the output, and the output voltage starts increasing.