Yes, as Pqass explained. The one key factor you are forgetting is the electron current through the tube, emitted from the filament surface, accelerated by the active digit's positive grid, (which also intercepts a small proportion of it), and terminating at the active segments, which are positive anodes. For analysis consider this as an equal and opposite conventional current flowing from +HT through the high side of the active segments' and grid's drivers, through the tube to the filament cathode, then through the center tap resistors and through the Zener to ground, keeping it biased at its breakdown voltage. This current is limited by the tube characteristics, so for analysis of the filament drive and bias circuit can be considered as a DC current source feeding the Zener cathode.