Notice the condition in note 5, VDD = 60V. The inductor provides 57.6mJ of boost on top of the 60V supply. We need to know the actual breakdown voltage to calculate this, which isn't easy to know: only a minimum (75V) is given, and it varies during the pulse anyway. Using 90V as a SWAG, then the inductor would deposit 57.6mJ at 90 - 60 = 30V, but the device sees 90V therefore the total was (57.6mJ * 90V / 30V) = 172.8mJ.
Alternately, we can use the same argument to measure the average breakdown voltage. Since they give the 149mJ figure, evidently Vbr is even higher, (60V) * (149mJ) / (149mJ - 57.6mJ) = 97.8V.
Which sounds like a generous safety factor, but there are multiple reasons to avoid operating continuously above the rated 75V.
The energy figures match up much more closely in most datasheets, where a lower VDD is used (for example, 10V supply into a 600V MOSFET); it is peculiar that they used such a high value here.
Tim