Electronics > Projects, Designs, and Technical Stuff
Difference between the VNLD5300 and VNLD5090
drakejest:
I have been looking for a low-side mosfet driver IC and found these VNLD5300 which is a 300mOhm 2A driver and the VNLD5090 which is a 90mOhm 13A driver. I would like to do one last sanity check, the 5090 seems to be a much more superior IC am i right? But what strikes me is as weird for the same package can the 5090 really handle that current? they are priced very close too so i assumed that ST electronics made these 2 version intentionally with different purposes.
My application is controll and inductive coil at 1.5A both IC fit the application, would going for the 13A 5090 good for me ? What could the reason be that there is a skew with an inferior rating, because i dont think its cost, since they are priced that close.
magic:
It can only handle 13A peak, not continuously - do the math on power dissipation. It will discharge your gate much faster than the other chip, though.
I imagine one reason for preferring a slower driver, besides price, may be less switching EMI.
drakejest:
--- Quote from: magic on August 13, 2020, 06:41:45 am ---It can only handle 13A peak, not continuously
--- End quote ---
I assumed that the higher value amperage was the peak (25 A for the VNLD5090). Having a second look at it, i could not find the true maximum current for the device and is written as "internally limited" under the electrical characteristics
--- Quote from: magic on August 13, 2020, 06:41:45 am --- do the math on power dissipation.
--- End quote ---
can you guide me sir on how to do this ? what parameters should i use and how do i use them so that i can know if im safe on my application on open air with no heatsinks?
magic:
For continuous current through the output stage MOSFET it's simply I²·RDS(on), like with any other MOSFET.
When driving an external FET, it depends on gate charge and switching frequency.
drakejest:
--- Quote from: magic on August 13, 2020, 07:10:49 am ---For continuous current through the output stage MOSFET it's simply I²·RDS(on), like with any other MOSFET.
--- End quote ---
I do not quite understand how to use the formula, Isnt that a formula for power P=I²·R. I am missing the P, R is 0.09 ohms, I² is my missing variable. So i cant solve the continue current
--- Quote from: magic on August 13, 2020, 07:10:49 am ---When driving an external FET, it depends on gate charge and switching frequency.
--- End quote ---
can we assume then 100% uptime?
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