Electronics > Projects, Designs, and Technical Stuff
DIY cheap powerbank (technical suggestions R welcome !)
crazyguy:
--- Quote from: ym58 on August 10, 2016, 07:51:30 am ---
--- Quote from: crazyguy on August 09, 2016, 04:55:00 pm ---very cheap chip
Power Bank SoC
http://www.injoinic.com/english.html
IP5108
Charger Current 2.5A, Boost Converter Output Current 2.1A
http://www.injoinic.com/doc/IP5108_brief.pdf
http://www.gearbest.com/chargers/pp_421906.html?wid=21
http://www.chongdiantou.com/thread-2357-1-1.html
--- End quote ---
Hello Crazyguy,
A few questions :
Thanks !
--- End quote ---
(1) The IP5108 brief datasheet said VREG (pin 12) is 3.1V LDO Regulator Output, 50mA (max)
I think it means the L4 (pin 13) is connected to the VREG (pin 12)
IP5108 datasheet
http://www.injoinic.com/doc/IP5108_brief.pdf
(2) the table
green color -> IC Part Number, IP5101 ....
yellow color -> discharge current (A)
pink color -> charge current (A)
(3) according to the package, I would guess it is a IP5108 chip
https://item.taobao.com/item.htm?id=534722661076&ns=1&abbucket=5#detail
ym58:
--- Quote from: crazyguy on August 10, 2016, 08:11:28 am ---(1) The IP5108 brief datasheet said VREG (pin 12) is 3.1V LDO Regulator Output, 50mA (max)
I think it means the L4 (pin 13) is connected to the VREG (pin 12)
--- End quote ---
I am not quite sure I understand how VREG works.
What that 3.1V LDO Output is supposed to control ?
And why should TWO outputs (VREG and L4) be connected together ?
--- Quote from: crazyguy on August 10, 2016, 08:11:28 am ---yellow color -> discharge current (A)
pink color -> charge current (A)
--- End quote ---
Just to make sure I got it all clear :
Charge = constant current (CC) delivered by the chip to the batteries during the charge cycle
Discharge = current that the chip is able to output to the load (smartphone, iPhone ...) via the two 5V/VOUT pins (5-6)
Is that correct ?
ym58:
--- Quote from: blueskull on August 10, 2016, 09:50:28 am ---Form the datasheet it says VREG is regulator output. The reason they are connected to L4 is because (I guess) L1 and L4 are also logic inputs sampled at power up, to determine whether the IC operates in 3 LED, 4 LED or 5 LED mode.
--- End quote ---
crazyguy:
--- Quote from: ym58 on August 10, 2016, 09:56:46 am ---
--- Quote from: blueskull on August 10, 2016, 09:50:28 am ---Form the datasheet it says VREG is regulator output. The reason they are connected to L4 is because (I guess) L1 and L4 are also logic inputs sampled at power up, to determine whether the IC operates in 3 LED, 4 LED or 5 LED mode.
--- End quote ---
--- End quote ---
yes, you are right, 3, 4 and 5 LED configuration used for battery level indication.
crazyguy:
--- Quote from: ym58 on August 10, 2016, 09:43:10 am ---
--- Quote from: crazyguy on August 10, 2016, 08:11:28 am ---(1) The IP5108 brief datasheet said VREG (pin 12) is 3.1V LDO Regulator Output, 50mA (max)
I think it means the L4 (pin 13) is connected to the VREG (pin 12)
--- End quote ---
I am not quite sure I understand how VREG works.
What that 3.1V LDO Output is supposed to control ?
And why should TWO outputs (VREG and L4) be connected together ?
--- Quote from: crazyguy on August 10, 2016, 08:11:28 am ---yellow color -> discharge current (A)
pink color -> charge current (A)
--- End quote ---
Just to make sure I got it all clear :
Charge = constant current (CC) delivered by the chip to the batteries during the charge cycle
Discharge = current that the chip is able to output to the load (smartphone, iPhone ...) via the two 5V/VOUT pins (5-6)
Is that correct ?
--- End quote ---
IP5108 is a 2 in 1 power bank solution (charger + booster)
correct, Charge means (battery charger current), Discharge means (boost converter output current)
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