Yes, when the equivalent circuit has a resistor (series or parallel), that resistor looks like a noise-free resistance in series with Johnson noise voltage generator (or in parallel with a noise current generator) at that location in the circuit. One or the other, not both.
For narrow frequency bands, you can lump all the circuit losses into one such resistor.
You may need to use more than one resistor for wider band calculations, where the noise generators are statistically independent.
This is how Spice calculates such circuits.
Obviously, calculating the noise at the designated output of the circuit will have a frequency dependence from the tuned circuit.
For wider frequency band, depending on how that resistance was calculated, the resistance itself may be frequency dependent.
Decades ago, I faced exactly this situation with resonant sensor coils in MRI systems, where the bandwidth of the receiver system was narrow, centered on the sensor resonance, and the conductivity of the patient was an important part of the sensor Q.