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Find highest value of 4 inputs without microcontroller?
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spec:

--- Quote from: GeorgeOfTheJungle on November 19, 2018, 12:49:46 pm ---I've heard there's a 3 cents^W 7 cents µC with twelve twelve bits ADCs: pms132.

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Wow 12 bits: that is useful. Thanks for posting
spec:

--- Quote from: T3sl4co1l on November 19, 2018, 06:35:01 pm ---Yabbut... you need imagination to do design. I interpreted this thread as a design thread.  Can words not generate an image in your mind? ???

Tim
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I think we have seen the difference between imagination and an actual circuit. Would you kindly desist. I am only interested in technical matters.
spec:

--- Quote from: SiliconWizard on November 18, 2018, 08:44:32 pm ---
--- Quote from: spec on November 18, 2018, 08:40:13 pm ---It's a tantalizing problem-  you just feel that there ought to be a simpler way, and of course there is: a tiny MCU Sorry I mentioned that word  :palm:

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In terms of part count, obviously ;D
Although, depending on your input voltage sources, you may need additional buffering anyway - so wouldn't be that clear then!
Also, you'd be limited to the MCU's Vdd, whereas the opamp based design gives you a lot more freedom.

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Ah yes! I hadn't thought about voltage range :palm: It's always the simple things that get you.
T3sl4co1l:
Voltage range is easy, put a divider in front of everything. ;D  (Matched resistors, of course.)

Visual aid: https://www.seventransistorlabs.com/Calc/ResDiv.html#three
a calculator I wrote just for this kind of purpose, actually. :)

Tim
spec:
Nice one Tim. So the parts count is MCU + 8 resistors: two resistors per channel. I don't know about you all, but that circuit would get my vote. :)

It has the advantages of simplicity, low cost, and flexibility. To add another input just requires 2 more resistors.

Can you please post a schematic of this attenuator approach that you speak of- sorry, couldn't resist it :-DD
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