Electronics > Projects, Designs, and Technical Stuff

Help with how this PSU works. (With revised design)

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xavier60:
That should cover everything.
Modern LEDs are so efficient, only a small current, as low as 0.3mA.

Evangelopoulos Panagiotis:

--- Quote from: xavier60 on May 13, 2020, 09:58:28 am ---That should cover everything.
Modern LEDs are so efficient, only a small current, as low as 0.3mA.

--- End quote ---

Awesome! I learned quite a bit from this project. I shall start the board design now.

Thank you Xavier for the help. I really appreciate it.  :-+
 

Evangelopoulos Panagiotis:
I completed the project thanks to the help of you all.

Let's hope it actually works!  :scared:

The project can be found below incase someone wants to build one. 
https://easyeda.com/EvangelopoulosPanagiotis/Linear-Current-Limiting-PSU

Please excuse my rushed board design.

Have a nice day!
E.P.

Dave:
The fuse protecting the negative clamping diode on the output makes no sense. Let's say the user accidentally connects another power source to your PSU backwards. A large current flows through that diode, the fuse blows. You just saved a 5 cent diode and sacrificed 30€ worth of other components to do it.

If you decide to use a fuse to protect the output, it should be wired in a way that it cuts the circuit when an overload causes it to burst, thus protecting the power supply. In series with the output would be fine (the resistance of the fuse is going to increase the output impedance of the power supply, but it shouldn't be too bad).

Evangelopoulos Panagiotis:

--- Quote from: Dave on May 13, 2020, 06:11:27 pm ---The fuse protecting the negative clamping diode on the output makes no sense. Let's say the user accidentally connects another power source to your PSU backwards. A large current flows through that diode, the fuse blows. You just saved a 5 cent diode and sacrificed 30€ worth of other components to do it.

If you decide to use a fuse to protect the output, it should be wired in a way that it cuts the circuit when an overload causes it to burst, thus protecting the power supply. In series with the output would be fine (the resistance of the fuse is going to increase the output impedance of the power supply, but it shouldn't be too bad).

--- End quote ---

Damn you're right... Why did I thought it would save the rest?  :palm: I'll put the fuse in series.

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