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High efficiency DIY buck converter

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T3sl4co1l:
If you want something probably-better than Ali junk, and don't have the time/money/tools to produce a board yourself: consider getting a dev board for one of the regulators.  This will be under $100 for that price range I think, and is ready to go, give or take swapping some resistor values to set the desired output voltage and such.

Tim

splin:

--- Quote from: T3sl4co1l on September 21, 2019, 02:33:08 am ---If you want something probably-better than Ali junk, and don't have the time/money/tools to produce a board yourself: consider getting a dev board for one of the regulators.  This will be under $100 for that price range I think, and is ready to go, give or take swapping some resistor values to set the desired output voltage and such.

Tim

--- End quote ---

Nooooo! Don't consider a dev/evaluation board - far too expensive! Just go to digikey, or your favourite distributer and plug in your requirements. Here's one @ $7, one off:

https://www.digikey.com/product-detail/en/bel-power-solutions/SLDN-12D1ALG/179-3029-ND/8028727

95% efficiency (according to spec) with 12V input, 5V out @ 8A. Don't like that one? There are plenty more for < $10.

T3sl4co1l:
That is, if you weren't going for a drop in module, indeed. ;D

Tim

Warhawk:
Ti has been publishing reference and power designs online. You can try to have a look http://www.ti.com/reference-designs/index.html

e.g. http://www.ti.com/tool/PMP30101

drummerdimitri:
I ended up adding a fan on top of the buck module and it is almost silent due to it's small size even though I was reluctant to do so, it seemed like the correct way forward.

Now I'm trying to chose a switch with the lowest resistance to keep efficiency as high as possible without going for a ridiculously large one but I'm not sure how to calculate the power loss if I know its resistance (4 wire method)?  :palm:

I can do ohms law but not sure about voltage drop/power loss calculations.

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