A wirewound resistor behaves like a fuse
This is just ridiculous.
Yes, of course a wirewound resistor finally blows open-circuit, like a fuse.
It's well capable of starting a fire before that happens, though!
A fuse does not start a fire as a normal part of fusing. That's the difference, and that's why any wirewound resistor isn't a fuse.
There is a thing called "FUSIBLE RESISTOR" which conforms to your description "behaves like a fuse". Just getting a "wirewound resistor" doesn't mean you'll get a fusible resistor. Get one RATED for that, if you want it. Nevertheless, even fusible resistors have the tendency of causing serious damage around, and the common practice is to consider placement carefully, then use glass fiber - silicone sleeving to thermally insulate the part.
The concept of SOA applies to the complete system or combination of parts, in this case the resistor, its protection, and the surrounding components sensitive to heat.
You clearly lack the ability to properly design such circuit, let alone give advice about it.
You should be more reserved before expressing personal opinions on my skills so as not to make a fool of yourself.
You don't know me, you don't know my qualifications, or my professional experience, so I wonder what criteria you allow yourself to judge me on.
In addition, it is not fair play and against the rules of this forum.
The main component of a wire-wound resistor is a wire, as is the case with a fuse, and during a short-lived strong current pulse, the heat transfer coefficient between the wire and the body of the resistance and his thermal resistance can be overlooked.
With a high peak current, the wire melts; like a fuse would.
For high impulse currents, it is therefore the i²dt which is the upper physical limit of destruction of the resistance.
This defines what is the maximum peak current that the resistor can withstand and for how long without being destroyed, being clear that these are only very short pulses.
This is what happen when charging a capacitor....High initial peak current who drops to 37% of his value after T (time constant) and to 13% after 2T.
The number of joules that will be dissipated in the resistor during the capacitor recharge sequence can easily be calculated.
It is enough to check if this dissipated power will not raise the temperature of the resistance beyond the permit, taking into account the thermal inertia of the resistance.
For the application of OP, he could choose a 33R 50W resistor.
NB: If the temperature of the wirewound resistor exceeds the allowable limit temperature, the resistor will not instantly be destroyed but its service life will be reduced.
This behavior is different from that of a semiconductor which suffers from other phenomena such as the second breakdown and instantaneous destruction and that is why the notion of SOA does not apply to a wirewound resistance