For a quick and crude simulation model you could use a DC voltage source in series with a huge capacitor and a small resistor. The DC voltage source will provide the "empty" battery voltage and the capacitor will model the charging and discharging state of the battery. The series resistor will model the internal battery resistance (typically few milliohms or so). The model is not accurate but it should be a usable starting point so that you can get started with the simulation until you find a better model.
For a nominal 12V and 200A car battery the model could be something like this:
- Capacity 200Ah
- Minimum battery voltage 11V (fully discharged)
- Maximum battery voltage 13.5V (fully charged)
Thus, the model can be constructed as follows:
- DC voltage: 11V.
- Capacitance: 288000F.
- Resistance: 5 milliohms.
The capacitance value can be calculated as follows: C = Ah * 3600 / V, in which the V is voltage difference between the maximum and the minimum battery voltages. For example in 200Ah battery case the capacitor C can be calculated like this: C = 200 Ah * 3600s / 2.5V = 288000 F. (Yes, it is a huge capacitance value)
You may find the following article useful:
http://batteryuniversity.com/learn/article/charging_the_lead_acid_battery