As I said, I tried to do exactly what you tell, but camera isn't starting.
In the first post I think you said you tried a Zener diode and a resistor. That's not likely exactly how it would be setup in the battery, so perhaps a brief note on how thermistors are used will help you (or at least it might help somebody in the future who stumbles across this thread)...
A thermistor has a specified resistance (say 10k) at a very specific temperature (25 C). The resistance changes in a known fashion depending on the temperature. So if you know the immediate resistance, you can calculate (or look up) the temperature.
Of course, to know that immediate resistance you can apply Ohm's law - but that means you have to know both the voltage, and the current if you want to calculate the resistance.
So you form a voltage divider using a resistor of a known resistance.
(+) -- [known R] -(midpoint)- [ thermistor] -- (-)
Now you can easily measure the voltage at (+) and at (midpoint) and at (-) if it's not zero.
So now you know the (+) voltage, you know the [known R] and you read the (midpoint) voltage, Ohm's law gives the current through the known resistor and we assume that the measurement at midpoint is high impedance, so therefore the current through thermistor is the same.
Now you know the current through the thermistor, and you know the voltage at midpoint, so simple Ohm's law gives you the current resistance of the thermistor.
Now you know the resistance of the thermistor, you can calculate (or lookup from a table) the temperature of the thermistor.
For a typical NTC thermistor, the calculation of temperature is...
TemperatureC = 1 / ( (natural_log( Rthermistor / RthermistorAt25C ) / Beta) + (1 / 298.15) ) - 273.15
Beta value depends on the thermistor, but 3950 is a good guess if you don't know it, for clarity I'll note that 298.15 is 25 degrees C in Kelvin, and 273.15 is 0 degrees C in Kelvin.
So, what does this mean for you? The unknown pin of your battery is likely to be the midpoint of such a voltage divider. It would be a reasonable guess that the thermistor is 10k at 25 degrees C because that's common, and it would be a reasonable guess that the resistor is 10k because that's convenient, but you should be able to measure both if you can find them in the existing circuit.
Where does the zener come into it? If there's a zener there at all, then it will be forming the reference across which this voltage divider is attached (thereby negating the need to measure the (+) because it will always be the zener voltage), see attached...