Electronics > Projects, Designs, and Technical Stuff

my own original oscillator

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joeqsmith:

--- Quote from: krayvonk on July 07, 2019, 02:46:44 am --- |O

ah dont worry about it.  I shouldnt be letting my tech get stolen anyway.


Your better off with transistors anyway, who cares.

Didnt even try it...

--- End quote ---

Correct, I did not try it.   Mainly because I know the outcome by just looking at your circuit.  It's possible you have something else going on that you don't understand.  This buzzer you mention on the side may be part of it. 

The circuit would be easy enough for you to model in SPICE to help you understand what is going on.  Maybe once you have a better idea of why it oscillates, you can report back and we can try to replicate your findings. 

I'm not seeing the whole "stolen tech".    There is nothing novel about turning on a couple of LEDs, which is what you currently are showing.  If you could come up with something new and wanted to try and patent it, you would need to explain it.   

krayvonk:
It looks funny how there is a positive right near the negative and it sneakily looks like voltage loss.

When the capacitor is empty it charges through,  only once that pole is blocked does it dump out the back pole, and thats so i dont turn off the other side UNLESS its using the through cap going pole.(*)

the resistor balance 4,2,1,   makes sure the discharge "loop" is never taken over 2&1.  and the 1, through capacitor line will always overscede the 2,  the voltage loss pole.  the loss pole is activated to make sure i dont run around the cap and cause it to still the inversion at a constant power!(*)

the 4 resistor, the heavy one, cant be too heavy because its the discharge speed, it was constantly stressing me out because it might not have worked.

You temporarily had me befuddled when you simplified my topology, and it even made me understand it better in the end thanks! :D    ur circuit is equivilent i was making a mistake.


(*) same point in different words.

joeqsmith:

--- Quote from: krayvonk on July 07, 2019, 04:19:35 am ---It looks funny how there is a positive right near the negative and it sneakily looks like voltage loss.

When the capacitor is empty it charges through,  only once that pole is blocked does it dump out the back pole, and thats so i dont turn off the other side UNLESS its using the through cap going pole.

the resistor balance 4,2,1,   makes sure the discharge path is never taken over 2&1.  and the 1, through capacitor line will always overscede the 2,  the voltage loss pole.

You temporarily had me befuddled when you simplified my topology, and it even made me understand it better! :D    ur circuit is equivilent i was making a mistake.

--- End quote ---

You should use common terms.   Poles and zeros may mean something different to me than you.   The way you use poles and back poles, it means nothing to me. 

There is no discharge path with what you show, shy of removing the power.  The caps will both charge at the same rate and reach a steady state value.   At that time, they will both have the same value.  That much should be obvious.   As a mater of fact, you could calculate all of this easy enough.   

krayvonk:
Your thinking is correct on that one,  and both caps will fill and will not toggle, it does actually do that sometimes.  and it just turns off, even with the battery connected, it is one of its possible states.  Also probably even blended 50/50 travel happens too,  and pessimisticly you can not bother with it.

There is a way to relay-start it on so one cap starts charged and one starts empty, but funnily it tends to oscillate without it, and u can connect and itll find the imbalance itself.

When I say discharge path, i literally just mean putting the capacitor in a little loop.   and it needs this guard "positive" to make sure it never takes the route of 4 resistance in the loop, over 2 resistance to the guard "positive".   (therefore its variable what hits the opposing "positive" to load thieve from the other side/phase.)  - from this sides negative.  which puts the other cap into discharge - (down its 4 resistor "loop",  and its lucky it wasnt too much resistance to slow its discharge down so slow that it didnt work.)

So effectively the battery is changing which side its going,  one side always has a bigger percentage than the other, and it oscillates.

joeqsmith:
It would be easy enough to short one cap manually on startup.  The other will reach steady state and when you remove the short across the other, it too will reach steady state.   

If you don't own a decent camera, no problem.  You obviously have a PC of sorts.  Load up Linear Tech's free SPICE.   Enter your schematic.  You can include switches and what not to try and get it to start. See if you can show any case where it will oscillate.  If you do, then just post that circuit and we can go from there. 

If you followed that link to look at some of the oscillators,  an easier one is just using your resistor and one LED.   A bit faster than 1Hz.

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