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| Power consumption of circuit |
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| Prehistoricman:
--- Quote from: Chalcogenide on March 27, 2020, 09:43:55 pm --- --- Quote from: raff5184 on March 27, 2020, 09:09:37 pm ---I want it fully off, how do I do it? --- End quote --- Connect its inputs + and - to gnd and vdd, respectively. This will force its output to 0V. The other way around is also fine. --- End quote --- Quite possibly one of these states will have less consumption than the other. Worth checking out briefly. |
| Vovk_Z:
--- Quote from: raff5184 on March 27, 2020, 09:09:37 pm ---I want it fully off, how do I do it? --- End quote --- Here is Application Design Guidelines for LM339, LM393, TL331. Look page 13 "5.1.2 Unused Comparator Input Connections". Here is opamp design notes. |
| raff5184:
--- Quote from: StillTrying on March 27, 2020, 10:03:14 pm ---The CPC1114N needs a resistor in series with it, to supply it with about 2 to 5 mA. --- End quote --- It works without the series resistor and it doesn't absorb as much current, but apparently it is not the proper way of doing it. So, do you know of any Form B relays that can be activated with current in the order of microamps? Even a digital switch that can work with a supply as low as 1.5-2V would work. All the relays I found need >1mA, which is at least 3x more current than the remaining part of the circuit absorbs |
| raff5184:
--- Quote from: daqq on March 27, 2020, 09:48:11 pm ---Also, why are you trying to power the comparator by a voltage reference and a shunt resistor (R1)? Can't you just connect it directly to the battery? --- End quote --- That's because like I said I was trying to keep the Vs, Vin and Vref independent from each other. But since I already have a reference (LM285) for Vref I don't need it any more on Vs. However I still use a 33k Ohm between the Vbatt+ and the supply of the comparator to limit the supply current, otherwise it is too high |
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