Author Topic: Calculate Measurement Error  (Read 2403 times)

0 Members and 1 Guest are viewing this topic.

Offline ludzincTopic starter

  • Supporter
  • ****
  • Posts: 506
  • Country: au
    • My Misadventures In Engineering
Calculate Measurement Error
« on: April 05, 2016, 06:25:45 am »
This is a question that I got wrong 20 years ago in my Uni Physics days, and I still don't know how to get it right....

Assume I'm measuring the results of an experiment and I need to take three different measures (assume length, weight and temperature).

If my length measurement has an error (accuracy) of 1%, my weight measurement has an error of 2% and my temperature measurement has an error of 5%, what is the overall error of my system?

Do I just sum the percentages? (HINT:  No, I did that and failed, and I never learnt why....)

Thanks all.



 

Offline zlymex

  • Frequent Contributor
  • **
  • Posts: 556
  • Country: cn
Re: Calculate Measurement Error
« Reply #1 on: April 05, 2016, 06:36:49 am »
Normally in a RSS(root-sum-square) way if these three variables are all directly related to the final result.
overall error  = sqrt(1%^2+2%^2+5%^2)=5.5%
 

Offline Krampmeier

  • Regular Contributor
  • *
  • Posts: 91
  • Country: de
Re: Calculate Measurement Error
« Reply #2 on: April 05, 2016, 08:44:34 am »
@zlymex: Correct, that is how measurement uncertainties are usually added. That is, if all the errors are uncorrelated. It also depends on how the system processes the individual values (add/substract or multiply/divide/power/...).

@ludzinc: You may want to start reading https://www.wmo.int/pages/prog/gcos/documents/gruanmanuals/UK_NPL/mgpg11.pdf at chapter 7.2 or, if you really do like formulas, check chapter 5 of http://www.bipm.org/utils/common/documents/jcgm/JCGM_100_2008_E.pdf.
 
The following users thanked this post: MK14

Offline ludzincTopic starter

  • Supporter
  • ****
  • Posts: 506
  • Country: au
    • My Misadventures In Engineering
Re: Calculate Measurement Error
« Reply #3 on: April 05, 2016, 10:52:44 am »
Thanks!

I can see I have some light reading at bed time tonight ;)
 


Share me

Digg  Facebook  SlashDot  Delicious  Technorati  Twitter  Google  Yahoo
Smf