Hi!

Been here for awhile,
Doing my bit....
but now, I have ran into a wall....
This seems tricky, so I decided to ask the internet experts.
Let me explain.
I am working on series resonant circuits using halfbridge driver inputs.
My task that I assigned myself, is to measure the series resistance of all relevent real resistance of series resonant circuits.
The total resistant of series resonant circuits can be measured indirectly by measuring the V(p) output of a series resonant circuit accross the capacitor by calculation.
The total resistance of a series resoanat circuit includes:
R(dc) = wire resistance
R(ac) = wire eddy current resistance
R(di) = dielectric resistance [parasitic capacitance]
R(core) = core resistance
R(ESR) = equivilent series resistance of the capacitor in resonance
R(connection) = series resistance of all connecting wires and average of the R(ds)on of the N and P channel mosfets.
R(dc), R(ESR), and R(connection) are easily measured with my mastech MS5308 LCR meter and my mastech MS8040 digital multimeter(s) which have been calibrated to 10V DC under the DC setting with a voltage reference with an error of 0.002% error at 25 degrees C.
The MS5308 LCR meter allows me to measure the dissipation factor of the wire insulation by binding up a bundle of wire and using it like a capacitor. The dissipation of the heavy insulated polyimide wire is about 0.0056 at 10kHz, which follows manufacturing datasheets of dissipation between 0.006 an 0.005 of the most commonly use polyimide at 1 mm thickness between frequencies of 1khz to 10khz. (As frequency decreases, DF decreases)
I have measured this 2inch 60u MPP inductor that I have hand wraped with 24 sections on my LCR meter, and it is stating a Q between 250 and 300. The LCR meter's Vpp is 2V. Althought the range is consistant, the actual value does not seem to be consistant.
When the inductor is used under load within the series resonant circuit, the Q of the inductor is dramatically decreased to about 190. This can only be explained by either the R(core) or the R(di).
The R(core) is voltage dependent and fits the leggs equation very accurately, which leaves R(di).
My exact question involves these values:
R(dc) = 13.24 ohms
R(ac) = 0 ohms
R(core) = 8.3 ohms
R(ESR) = 2.17 ohms
R(connection) = 2.55 ohms
+/-10V input squarewave
6240 hz RF
374 pF parasistic capacitance
0.0045 DF polyimide wire isulation
128.35 mH MPP inducator
4.694 nF metalized polypropylene capacitor with 0.0004 DF at 10khz
output Vp 1250
ouput I in avg 148.4mA
Unaccounted for resistance = 22.7 ohms
I'm thinking this is parasitic capacitance because these resistance is not voltage dependent.
My question is:
How do I calculate the exact amount of series resisance associated with an inductor from a parasitic capacitance with a certain amount of dissipation from the wire insulation.
BTW, it should equal about 22 to 23 ohms.