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| Simple DIY Linear PSU |
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| xavier60:
--- Quote from: panoss on March 14, 2020, 09:12:03 pm ---Well, I replaced: -the S8550 with the BC557 -the LM317 with another LM317 Results are the same. --- End quote --- Just with the 20 ohm load, measure all of the voltages in the output stage, Q2 Emitter Q2 Base Q2 Collector Q3 Emitter Q3 Base Q3 Collector With respect to the top end of the CS resistor. |
| panoss:
--- Quote from: xavier60 on March 14, 2020, 09:15:35 pm ---With respect to the top end of the CS resistor. --- End quote --- Which is the CS resistor? |
| xavier60:
--- Quote from: panoss on March 14, 2020, 09:27:14 pm --- --- Quote from: xavier60 on March 14, 2020, 09:15:35 pm ---With respect to the top end of the CS resistor. --- End quote --- Which is the CS resistor? --- End quote --- The Current Sense resistor R18. Always take measurements with respect to the end that connects to the negative output terminal, What value is it? |
| panoss:
R18 is two 100m resistors in parallel, so it's 50milliohm. |
| panoss:
Input voltage: 12V. RL=20 Ohms. Q2: Ve=11.67V Vb=10.83V Vc=11.58V Q3: Ve=11.66V Vb=11.59V Vc=10.30V |
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