Electronics > Projects, Designs, and Technical Stuff
Simple DIY Linear PSU
xavier60:
--- Quote from: panoss on March 14, 2020, 09:12:03 pm ---Well, I replaced:
-the S8550 with the BC557
-the LM317 with another LM317
Results are the same.
--- End quote ---
Just with the 20 ohm load, measure all of the voltages in the output stage,
Q2 Emitter
Q2 Base
Q2 Collector
Q3 Emitter
Q3 Base
Q3 Collector
With respect to the top end of the CS resistor.
panoss:
--- Quote from: xavier60 on March 14, 2020, 09:15:35 pm ---With respect to the top end of the CS resistor.
--- End quote ---
Which is the CS resistor?
xavier60:
--- Quote from: panoss on March 14, 2020, 09:27:14 pm ---
--- Quote from: xavier60 on March 14, 2020, 09:15:35 pm ---With respect to the top end of the CS resistor.
--- End quote ---
Which is the CS resistor?
--- End quote ---
The Current Sense resistor R18. Always take measurements with respect to the end that connects to the negative output terminal,
What value is it?
panoss:
R18 is two 100m resistors in parallel, so it's 50milliohm.
panoss:
Input voltage: 12V.
RL=20 Ohms.
Q2:
Ve=11.67V
Vb=10.83V
Vc=11.58V
Q3:
Ve=11.66V
Vb=11.59V
Vc=10.30V
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