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| TI TPS61235P boost converter IC question |
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| aiq25:
Hello. I'm planning to use a TI TPS61235P boost converter IC for an upcoming project (VOUT 5V/3.5A with a VIN_min of 3V). In the features TI mentions there are two 10A internal power switches for the synchronous function but in the headline it's mentioned as a 8A converter, where does this descripency come from? Also, the minimum value for I_LIM (switch valley current limit) is 6.5A. With an output of 5V at 3.5A, with a VIN of 3V the input current roughly be about (assuming 85% efficiency) 6.86A. This should work, according some of the efficiency plots I think this is doable with this IC but what is confusing me is the minimum value of I_LIM at 6.5A. Does this mean I should only draw 6.5A max at the input (since the IC can have this limit at the temperature extremes it seems)? In short, I'm not understanding how the 10A, 8A and the 6.5A are related. |
| aiq25:
I wanted to provide an answer, if anyone comes across this post. I posted this question on the TI E2E forum and got an answer. 6.5A is the limit. This was quite disappointing for me since these IC's are advertised as 8A in the datasheet title and 10A in the "Features" section. |
| Evan.Cornell:
Marketing != reality. |
| nuclearcat:
Most likely, these data do not indicate the maximum current of the converter. Maximum current greatly depends on the many parameters, frequency, Vin / Vout, heat dissipation capability, operating temperatures, components around and etc. And good advice, try to not pick anything that will operate near maximum limits of IC, always keep a good safety margin. |
| aiq25:
I typically add 10% margin to my worst case operating conditions and then try to have 10% margin on component parameters. I have learned quite a few things in designing this boost converter, which is good. |
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