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Turning off an LDO using a mosfet

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OM222O:
I'm trying to use a DPDT latching switch to turn on/off my entire project.
They are usually rated for something like 10mA but I've had no issues using them to connect/disconnect 1A! but that's still not good practice.
I thought about using the switch to drive the gate of the mosfet in order to turn on the LDO, this way the switch is only a signal and carries no load.
I'm already using the dual N channel fet (DMN3018SSS-13) multiple times on other parts of the board. unfortunately I can't do high side switching with a N channel fet, but it would be nice to reuse the same part. I was wondering what would happen if I were to disconnect the GND pin of the LDO using that fet? would that damage something or have some weird side effects? Would it be better to just use a P channel fet to disconnect the battery from LDO (high side switching)?

nsrmagazin:
This "10mA" is not likely for a relay. You must be mistaken. Its best to use the relay or change it with a high power relay.

Something from here maybe:
http://www.cfcbazar.com/page/3/?s=relay

LapTop006:
You can probably also find an equivalent regulator with an enable pin.

OM222O:
I didn't say I'm using a relay. It's a small 8x8mm DPDT latching push button!
I also don't want to swap out the LDO as it's bought in quantities for other projects.
If switching the ground pin isn't a viable option, the best solution for me is a cheap P channel fet rated for about 2-3A.

mariush:
Ask yourself if the savings you get from using that LDO because you bought it in volume for other projects, are more than the cost of adding an additional part and the circuit board area and potentially an extra resistor to discharge the mosfet.
LDOs are cheap, can be as cheap as a mosfet.

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