Author Topic: Using power supplies with common input + and output + (Not common ground)  (Read 4980 times)

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Offline FoxesRuleTopic starter

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Hi everyone :-)

I have recently come across the LSF01-K5B12SS non isolated regulator for around 1.8$ on Digikey which really sparked my interest as it is a really cheap way to power circuits from mains voltages (Or high voltage DC sources)
I have attached the datasheet for those that are interested...

The 12V version of the regulator can output 83mA and has a input voltage range of 15V DC to 380V DC (or 85V to 264V AC)

I decided to play around with it and came across an interesting dilemma... normally non-isolated regulators have common grounds, but this regulator has a common + rail. (The input and output + terminals are shorted out)
*Figure 1 and Figure 2*

So if you try to measure the input voltage through a voltage divider and a microcontroller ADC you have a problem. Many applications require the ability to measure the input voltage. (For example, for my application I would like to add a relay that switches off if there is undervoltage or overvoltage in the mains power supply)

If you connect the voltage divider and ADC to measure over the regulator + input and - output (pins 4 and 3) you will always measure 12V. If you add a diode between the regulator + output and the voltage divider, it does not fix the problem.
*Figure 3 and Schematic*

If you connect the voltage divider and the ADC to measure over the regulator + input and - input (Pins 1 and 2), then you bypass the regulator - input and - output pins, effectively bypassing the regulator.
*Figure 4*

A simple way to fix this is to use an isolated PSU such as the LS03-13B12R3, however, in the spirit of learning electronics 😊 I really would like see if there is a way around this problem of using a power supply that has a common positive rail as opposed to a common ground for the inputs and outputs.

Is there any simpler and cheaper way to use the LSF01-K5B12SS non-isolated regulator and still be able to measure the voltage input with a microcontroller? I feel like I am missing some obvious solution to the problem...

Thank you!
-FoxesRule
« Last Edit: February 07, 2024, 08:36:46 am by FoxesRule »
 

Online tooki

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Re: Using power supplies with common input + and output + (Not common ground)
« Reply #1 on: February 10, 2024, 11:45:05 am »
Op-amp buffer?
 

Online Ian.M

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Re: Using power supplies with common input + and output + (Not common ground)
« Reply #2 on: February 10, 2024, 12:26:28 pm »
Return the 'lower' end of the input voltage potential divider to Uno 5V  rather than OUT-.   Note that there is an offset of 7V (due to the difference between Uno Vin held at 12V by the LFS01-K12 regulator, and Uno 5V), and the ADC result must be subtracted from 1023, then the result scaled by the divider factor before adding the offset.  For  AC input, add a diode in front of the divider so it only gets negative half cycles.

If you are using a bare MCU rather than a MCU module with onboard regulator, consider using a negative regulator to feed the MCU 'Gnd' so its Vcc can be the same as LFS01+common.  This gets rid of the offset.
« Last Edit: February 10, 2024, 12:34:16 pm by Ian.M »
 
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Offline GoStags

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Re: Using power supplies with common input + and output + (Not common ground)
« Reply #3 on: February 10, 2024, 12:37:15 pm »
Use a Linear Optoisolator.   A simple differential amplifier would also work but common mode rejection may make it inaccurate.
 
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