I don't understand by what you mean when you say temp-co does not matter.
The switch resistance together with the series resistance before the amplifier input forms a divider, the series resistance is around 100K (this is accurate both for the unattenuated path and for the attenuated path) and the amplifier input resistance is >1 GOhm. Lets say the switch resistance is 100Ohm and it has a 10000ppm tempco.
Lets ignore the tempco of the other resistors for a moment, so with a 1 degree shift we get a (1e9/(1e5+100+1e9)-1e9/(1e5+101+1e9))*1e6 ~= 0.001 ppm shift in the amplifier input signal.
They have one attenuated path (9.9M+100K attenuator) and one unattenuated path to the amplifier which they switch between with both relays and the mux, the amplifier does have a divider in it's feedback path which also uses part of the mux to change amplification. The same argument as above applies why tempco of the switch resistance is irrelevant.
PS. I should probably point out that the mux IC seems to provide voltage clamping to protect the amplifier (so with 1000 volt input after the primary voltage clamp the ~100K resistance before the mux limits current and the mux then clamps the voltage).