(? how do you get the pictures to show up in the message - I chose "inline expandable thumbnail, but it still puts them at the end?)
Here is an LT7101-based synchronous switching buck regulator, output 5V at 1A, input will be 36 to 59 volts.
Normally we would want a pretty solid ground, right? I'm not sure the best way to attach PGND to GND. Initially I considered a filter bead like the one I show on the 5V output, I believe it's 100 ohm at 100 kHz. The schematic shows a 0-ohm resistor, which could be a SMD, but I also considered creating a custom footprint that would have a solid copper area on another layer under the whole regulator circuit, connecting to a PGND pad on the input side and a GND pad on the output side.
But, a comment on
my first thread led me to consider something completely different: why not filter the ground side symmetrically with the + voltage side? I now believe the comment was geared specifically towards analog inputs, not the switching regulator circuit, but if the output is intended to operate on DC, and inductors and filter beads have very low impedance at DC, why not use them to filter out the high-frequency components from the ground side of the circuit as well as the non-ground side? So, I made this alternative schematic.
The incoming ground is PGND, then PGNDa, then LT_PGND and LT_SGND, then the outgoing ground is just GND. With inductors and filter beads between grounds to match the ones on the positive side. I guess, normally you wouldn't want to do this because if the ground went off-board at all, then someone would probably connect incoming and outgoing grounds externally, so the filtering would be for nothing. And, I do have some off-board LED strips that will be powered from the 5 volts. So: good idea? bad idea? I might simulate both in LTSpice and see what they look like.