Broken fusible resitor?

[Thyreen]

My 240v led light stopped working. When measuring continuity I probably found the problem in a blown fusible resistor (F1).
Can anyone confirm this indeed such a resistor, and am I correct it is 11 ohm and ?? watts. I think one color hides behind the metal cap?
The light iself has a maximum rating of 170ma.

[S. Petrukhin]

This is the fuse. It could have burned out from an external factor - a surge in voltage, or due to a circuit malfunction.

[bob91343]

Not really enough info, for me at least.  What are the colors?  That is a very tiny resistor, maybe 1/4 Watt or less.

So if you are drawing 170 mA it's probably protecting at somewhere near 250 mA.  For 1/4 W dissipation that would mean a voltage of 1 V across it and a resistance of 4 Ohms.  Maybe 11 Ohms seems high but maybe not.  Then that would mean with 170 mA a drop of 1.9 V or so and an operating power of maybe 320 mW.  Not impossible.  It just seems a lot for such a tiny part but with a 1/2 W rating it comes pretty close to reasonable.

[KevinA]

100mA Pico fuse

[Thyreen]

As far as I can see the colors are from right to left. Brown Black Black Gold

[james_s]

The question is, why did it fail? Fuses rarely fail for no reason, usually they are blown by an overload due to another failed part.

[aqibi2000]

Crude reactive ac voltage divider circuit from mains AC to power the LEDs.

My bet would be on a that electrolytic.

Worst case scenario is to be left with a shorted LED.

[Thyreen]

Well I have tried to apply power by bypassing the fuse and the light works. So apparently no harm to other devices. At least when it burns for a short amount of time.
In line there are also 3 CYT100A's Constant current led drivers max 60 mA each. Attached an extra image of the whole circuit.

To try it out would this component be any good?:
NFR2500004708JA500
Through Hole Resistor, Fusible, 4.7 ohm, NFR25 Series, 330 mW, ± 5%, Axial Leaded, 250 V

It would give a voltage drop of 846mV and power dissipation of 152 mW.

[S. Petrukhin]

There is no divider. The resistor is used as a fuse and for the release of high pulses closed by the varistor. After the resistor, a diode bridge and a capacitor are installed. The LEDs are connected in series with a total voltage of 230V. This is a very primitive scheme.

[S. Petrukhin]

It turns out that there is a current limiter. Most likely, the resistor, which is used here as a fuse, was killed by the varistor during a power surge in the supply line. You can install a fuse instead.