Hi all! New member speaking.
I acquired this Bluetooth speaker in faulty state without power adapter. It was described as failing to charge internal 7.4v battery and not turning on at all. I already have a smaller version (BTX300) using the same battery, so I plugged in a fully charged battery - yup no signs of life.
So I disassembled the unit and started probing the voltages using my cheap-ass meter. When I probed the transistor (?) Q713 (see the photo attached), I accidentally brought the unit to life. Apparently, when the battery is attached, the no1 leg voltage is around 3V and dropping, no2 voltage is 8V (same as battery), no3 voltage is 2.18V. Now the interesting thing is, when the negative probe is on the ground, and when I touch the leg no3 with the other probe, leg no1 goes up to 8V and the unit can be turned on. It works fine as long as the battery is connected. The resistor R730 just below the transistor is around 460K and feeds the leg no3 from 8V battery input.
My question is, when I probe leg no3 why the leg no1 goes up to 8V? How can I keep the unit doing this, I mean keeping leg no1 at 8V? Maybe I should add another resistor parallel to R730?
Sadly I don't have the correct charger, so I have no idea if the unit can keep the battery charged and get the required power from mains. This will be the second step.
No burnt components or broken solder joints.
Thanks in advance!
Koray