Puzzled by PLL voltages in a Kenwood R5000 Receiver

[jjbunn]

The attached schematic image shows part of a PLL in a Kenwood R5000 receiver.

I'm puzzled by the voltages shown around Q7, a 2SC2668 transistor, and hoping someone can explain them.

The Collector has a voltage of 2.8V, which is derived via R53 (1.2kOhm) from the supply of 8.6V. The Base has a marked voltage of 7.2V.

This does not make sense to me, so clearly I don't understand how the circuit functions! Shouldn't the Base voltage be set by the voltage divider R51/R52 (22k,33k), so about 22/55*2.7 i.e. ~1V?

How can the Base voltage be higher than the Collector voltage in this circuit?

Thanks!

[Kim Christensen]

I would guess that they've swapped the base and collector voltage labels by accident.
C = 7.2V
B = 2.8V
E = 2.2V

[jjbunn]

Yes! Measurements on the circuit show exactly that ... thanks for the comment!