The EEPROM appears to consist of variable length data records beginning with 0x5A and terminating in a checksum byte. The last byte of each record is the sum of all the previous bytes in that record. All checksums are OK.
There are several gaps filled with 0x00 or 0xFF, but I can't verify whether those are just placeholders.
These are the records:
5A 30 35 44 45 35 45 53 4D 38 30 30 30 38 38 42 DC
5A 07 00 61
5A (5A 00 00 00 26 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 01 81) 5C <-- record within a record
5A 00 02 01 04 02 01 00 00 F0 30 03 00 00 87
5A 00 00 02 00 00 00 00 00 00 00 00 00 00 00 00 00 00 74 1D 02 00 00 EF
5A 04 02 60
5A 00 02 01 04 02 01 00 00 F0 30 03 00 00 87
5A 00 00 00 00 25 00 02 00 01 00 00 00 00 00 00 00 82
5A 20 74 43 31 0B 0D 00 00 E8 00 00 00 00 00 00 00 00 62
5A 20 20 31 43 0A 0D 00 00 E8 00 00 00 00 00 00 00 00 0D
5A 20 20 4F 43 03 0D 00 00 E8 00 00 00 00 00 00 00 00 24
5A 20 20 64 43 07 04 16 63 17 00 00 00 00 00 00 00 00 DC
5A 20 20 55 62 06 04 42 63 1E 00 00 00 00 0A 00 00 00 28
5A 20 62 43 32 14 04 8A 5D 1D 00 00 03 00 08 06 00 00 7E
5A 20 20 64 43 07 04 3F 61 15 00 00 00 00 00 00 00 00 01
5A 0A 13 77
5A 00 02 01 04 02 01 00 00 F0 30 03 00 00 87
5A 00 09 00 00 00 06 00 00 20 0C 00 00 00 95
5A 00 02 01 04 02 06 00 00 F0 3C 03 00 00 98
5A 00 02 01 04 02 01 00 00 F0 30 03 00 00 87
5A 00 02 01 04 02 01 00 00 F0 30 03 00 00 87
This is the complete dump:
Offset(h) 00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
00000000 5A 30 35 44 45 35 45 53 4D 38 30 30 30 38 38 42 Z05DE5ESM800088B
00000010 DC 5A 07 00 61 00 00 00 00 00 00 00 00 00 00 00
00000020 00 00 00 00 00 00 5A 5A 00 00 00 26 00 00 00 00
00000030 00 00 00 00 00 00 00 00 00 00 00 01 81 5C 5A 00
00000040 02 01 04 02 01 00 00 F0 30 03 00 00 87 5A 00 00
00000050 02 00 00 00 00 00 00 00 00 00 00 00 00 00 00 74
00000060 1D 02 00 00 EF 5A 04 02 60 5A 00 02 01 04 02 01
00000070 00 00 F0 30 03 00 00 87 FF FF FF FF FF FF FF FF
00000080 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF
00000090 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF
000000A0 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF
000000B0 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF
000000C0 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF
000000D0 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF
000000E0 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF
000000F0 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF
00000100 5A 00 00 00 00 25 00 02 00 01 00 00 00 00 00 00
00000110 00 82 5A 20 74 43 31 0B 0D 00 00 E8 00 00 00 00
00000120 00 00 00 00 62 5A 20 20 31 43 0A 0D 00 00 E8 00
00000130 00 00 00 00 00 00 00 0D 5A 20 20 4F 43 03 0D 00
00000140 00 E8 00 00 00 00 00 00 00 00 24 5A 20 20 64 43
00000150 07 04 16 63 17 00 00 00 00 00 00 00 00 DC 5A 20
00000160 20 55 62 06 04 42 63 1E 00 00 00 00 0A 00 00 00
00000170 28 5A 20 62 43 32 14 04 8A 5D 1D 00 00 03 00 08
00000180 06 00 00 7E 5A 20 20 64 43 07 04 3F 61 15 00 00
00000190 00 00 00 00 00 00 01 00 00 00 00 00 00 00 00 00
000001A0 00 00 00 00 00 5A 0A 13 77 00 00 00 5A 00 02 01
000001B0 04 02 01 00 00 F0 30 03 00 00 87 5A 00 09 00 00
000001C0 00 06 00 00 20 0C 00 00 00 95 5A 00 02 01 04 02
000001D0 06 00 00 F0 3C 03 00 00 98 5A 00 02 01 04 02 01
000001E0 00 00 F0 30 03 00 00 87 5A 00 02 01 04 02 01 00
000001F0 00 F0 30 03 00 00 87 FF FF FF FF FF FF FF FF FF
Edit:
The 3rd record is peculiar:
5A 5A 00 00 00 26 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 01 81 5C
It appears to consist of a record within a record, and this sub-record also has a valid checksum.
5A 00 00 00 26 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 01 81