ignore the wrong position of the IC when I took a photo

I have based my design from here:
https://www.pcbway.com/blog/technology/DC_to_DC_Boost_Converter_using_UC3843.htmlUC3842 Datasheet:
https://www.mouser.com/datasheet/2/149/uc3843-309322.pdfThe problem is the output (15.7V) is just below the input voltage (16V), only change by the diode drop (0.3V).
The out pin of the IC also do not have any pulse. This is my first time doing analog stuff but I know the basic operation of a boost converter.
I don't understand exactly how the chip works.
I keep it at 16v as it is the UVLO on.
My goal is to have the output be greater than the input (16v) and my life is complete.
I have checked: every connection, values and no shorts, voltage coming to the IC, etc...
My components are limited only to what I salvaged, that's why I have different values.
But I have 10 UC3842 I bought online.
What do you think is the problem? Is the shunt resistor in series with Mosfet too high?
Is the Mosfet model incompatible?
Is the capacitance critical at Isense pin?
Are these UC3842 chips dead? (I've swapped them, same results)
I was surprised there is a shunt in the high-current Mosfet (efficiency?), does it need to be high power resistor like I used?
Is the board type inappropriate for my application?
Bonus question: Do current mode controlers do calculus? They seem to react with slope of current vs time from what I've read. Can't understand it tho.
What I have:
Lab PSU
Analog scope 60Mhz
2 DMMs
1st year EE
I'm already 4 days tried everything in my mental capacity. Any advice/tips or theory what's wrong?
THANK YOU SO MUCH!