Some backstory, I have an amplifier that needs to be repaired, and after some troubleshooting with the builder it was discovered that a specific IC (
?PC1237 [pdf]) had to be replaced. It's the 8-pin SIP in the middle of all the voltage measurements in the following picture:

No problem! I ordered the part, and in the meantime was trying to figure out how to get that daughterboard out . . . and just couldn't figure out how it was attached to the case. I sent an e-mail to the builder, and his response was that it was not removable, and to simply cut off the legs of the old IC and solder the new IC to the legs.
I've probably spent ~40 hours total soldering so I am still a beginner, and have never had to do something like this. I couldn't find anything on google about this procedure either. The biggest fear is that if I apply too much heat to the leg, I ruin the solder joint on the other side of the board which I cannot get to. I was going to try something like the following, but if anyone has any advice, a better procedure, or knows of a socket specifically designed for this purpose please share!
- Cut off the legs of the old IC
- Tin 8 pieces of extreemly short wire (<1 inch.) on both ends. Solder to the cut off legs being extreemly generous with flux and removing the iron as soon as the solder liquefies and bridges
- Heat-shrink the ends connected to the PCB
- Put some unshrunk heat-shrink over the wires, solder the new IC to the wires, and heat shrink the legs of the new IC
- Secure the IC to the board (haven't figure out the best way to do this one yet)