Regarding the AD8310 I perused the datasheet and it states it has an 1k input impedance. If you desire to present 50 ohms, connect a 52.3 ohm resistor in parallel with the input. You can see this in their own example in the datasheet. But what do the boards that Amazon have installed for that R? I see a 100 ohm resistor. Other people in the comments for this product noticed the same thing. So I'll have to remove that and put in a 50 ohm R (sorry no 52.3 ohm resistors at the moment).
That's why I don't trust the more built-up "power meter" that is for sale. I don't want anything in-between that chip and my testing. No telling what futzyness (is that a word?) they would have done adding more to it that I haven't approved of.

Analog Devices have used a scale of dBV, where 0 dBV = 1 V RMS, and so the output voltages are related to a dBV scale. If you desire dBm, and have the 50 ohm R installed, they state convert the voltage readings to dBm by adding 13 to the dBV number. So if their output from the chip is 2.5 V, it means the input is 1V RMS= 0 dBV which would be +13 dBm.
I also ran across an AD8307 board and in that datasheet Analog Devices presents a power meter design if you want to pick off readings. Should work for AD8310 too. I snipped it in case you wanted to consider anything about that for what you want to do. I just want to measure power single-ended from a transmitter for calibration purposes.