Hi,
I'm new to RF PA design, but am trying to figure out a design for a class-A MRF101AN Amplifier. I contacted NXP and am quoting below, their reply when I asked about tweaking their existing reference design board (designed for class-AB) to operate in class A.
Total power consumption of a class-A amplifier does not depend on the signal level. This amplifier dissipates maximum heat power when RF signal is off (RF power is zero). The heat power equals to RF power at maximum signal (50% efficiency).
Suppose a heat sink can dissipate 100W. Use thermal resistance value from MRF101AN datasheet. Junction-to-case temperature rise at 100W power dissipation will be dT=100*1.1['C/W]=110'C. To keep maximum junction temperature, the heat sink temperature must be less than Tj-dT=175['C]-110['C]=65'C. It looks reasonable.
Note! In class-A mode, the maximum RF power is 1/2 of maximum heat power dissipation -> maximum output power must be less than 50W to avoid overheat.
Example. If the heat sink temperature is 45'C then maximum dissipated power is (175-45)/1.1=118W -> maximum Rf power 118/2 = 59W.
NXP MRF101AN 88-108MHz RF board was designed for class-AB operation. It can't be used in class-A mode. The circuit need to be redesigned for operation in class-A mode.
The reason is that class-A mode requires different load impedance (larger value). If you simply increase quiescent current of the original circuit, the maximum power of the amplifier will exceed the limit.
The load line resistance is given approximately by: RL = VCC^2/(2*Pout)
In Class-AB mode, RL = 50^2/(2*100) = 12.5 Ohm
In Class-A mode, RL = 50^2/(2*50) = 25 Ohm
Actual load impedance value includes some reactance related to parasitic capacitance and inductance of the transistor. The estimated RL value for Class-AB mode is close to the load impedance values provided in the device datasheet.
So, from this, am I to understand that with a tweaked output impedance matching network, the board could work in class-A? I experimented a little in SimSmith to tweaked the matching network to match essentially double the impedance than what is provided in the data sheet (went to 26.24 + j10.42 FROM 13.12 + j5.21)
I don't have access to a proprietary tool like ADS to accurately model the device characteristics. Is there anything grossly wrong with this approach?
My next step is going to be trying this new matching network and setting Idq of 2A.