Author Topic: 53220A - is that spec. correct?  (Read 876 times)

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Offline carl_lab

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53220A - is that spec. correct?
« on: November 29, 2016, 11:37:26 am »
I don't understand, why aging rate for 2 years is below value of 1 year aging rate:

http://literature.cdn.keysight.com/litweb/pdf/5990-6283EN.pdf?id=1942617

Did they swapped 1yr ansd 2yr values by mistake?

For the standard oscillator (1ppm/yr) I would expect for 2 years aging something between 1 and 2 ppm (not 0.5 ppm)

What does this mean?
"All Timebase Aging Errors apply only after an initial 30-days of continuous powered operation and for a constant altitude ±100 m. After the first 1-year of operation, use ½ x (30-day and 1-year) aging rates shown."

« Last Edit: November 29, 2016, 12:06:19 pm by carl_lab »
 

Offline rf-loop

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Re: 53220A - is that spec. correct?
« Reply #1 on: November 29, 2016, 12:00:46 pm »
I believe it is right.

Aging is most fast when XTAL is new.

More long used and more slow aging typically.

Best aging curve is if  OCXO is continuously power on. (Example due to aging curve retract and possible other reasons.) After 5 year "pre-ageing" it may go nicely. (IF Owen temperature control is well done and perfect without long-time drift, etc)

If we look more deep about these things we find whole "mystery" world. More you know, things go more complex.

 http://kunz-pc.sce.carleton.ca/thesis/CrystalOscillators.pdf



« Last Edit: November 29, 2016, 12:04:41 pm by rf-loop »
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Offline HighVoltage

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Re: 53220A - is that spec. correct?
« Reply #2 on: November 29, 2016, 12:04:41 pm »
Yes, the numbers are correct, the instrument gets better over time.

The uncertainty after this time of continuous use is 1/2 of the day or year value.

There are 3 kinds of people in this world, those who can count and those who can not.
 

Offline carl_lab

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Re: 53220A - is that spec. correct?
« Reply #3 on: November 29, 2016, 12:14:45 pm »
I believe it is right.
Aging is most fast when XTAL is new.
More long used and more slow aging typically.
You said "more slow".
"More slow" for me means lower "change per time".

Then the "2yr" value is diffential change between t1=365 days and t2=730 days?
So if you want to calculate (absolute) change from t0=0 days (after initial 30 days "warming up") to t2=730 days, you have to add 1ppm+0.5ppm=1.5ppm ?
« Last Edit: November 29, 2016, 02:28:51 pm by carl_lab »
 


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