Products > Test Equipment
ET432 LCR Meter - Wild Results - Range Function?
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Veteran68:

--- Quote from: Randy222 on January 25, 2024, 12:55:11 am ---
--- Quote from: Veteran68 on January 25, 2024, 12:52:47 am ---
--- Quote from: Randy222 on January 24, 2024, 11:44:56 pm ---What FW version is your 1833C?

--- End quote ---

20210615AM
HW V1

--- End quote ---
I won't hijack this ET thread, but interesting, some are reporting a FW of "2023xxxxxxAM".
Thanks for noting it.

--- End quote ---

We can take the discussion over to the other thread, but I just looked and 20210615AM is still the latest version Hantek offers on their website. New units may be shipping with something newer -- isn't yours a brand new unit? What version is it?
Randy222:

--- Quote from: Veteran68 on January 25, 2024, 01:02:21 am ---

We can take the discussion over to the other thread, but I just looked and 20210615AM is still the latest version Hantek offers on their website. New units may be shipping with something newer -- isn't yours a brand new unit? What version is it?

--- End quote ---
I took this to the Hantek unlock thread.
killingtime:

--- Quote from: Randy222 on January 24, 2024, 11:44:56 pm ---Did you scope it in DCR mode just to verify it's really DC ?

--- End quote ---

Good question. Hooked it up to a scope and switched it into DCR mode.

The unit outputs a square wave. Period 2 seconds, 1.16 pk-pk voltage. Minimum voltage is 234mV. I don't think this would cause an issue though.

In LCR mode it outputs a sine wave. The default 600mV reading on the ET432 display is RMS according to my scope measurements. See scope cursors.

Attached.
Randy222:
0.5Hz 50% duty square, fo a Rdc measurement?

Just makes no sense to me. If the DUT is a large inductor then the hard rise and fall of sqaure wave "is" an issue.

Would really need to know how the meter runs the math to obtain Rdc from 0.5Hz 50%
mawyatt:
This is often done to reduce thermal EMF effects.

Math is simple, Thermal EMF effects don't change with test voltage polarity reversal. So subtracting the negative test voltage from the positive test voltage yields twice the peak voltage value while eliminating the thermal EMF effects as they subtract out  ;)

Best,
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