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| How long will it take to fill an oscilloscope's memory? |
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| ballsystemlord:
I was looking at oscilloscope specs (it's a bad habit I should learn to break ;) ), and I was trying to figure out how long it would take to fill up the memory of the scope. I've tried doing the math myself, but I'm pretty sure I didn't get math correct, so I'm turning to the community. Please note, I don't really *need* the answer. I'm just really curious. If I have a scope that samples at 5GS/s, does 64K wfm/s, and has 80Mpts of memory, how long would it take to fill the memory up? Thanks |
| egonotto:
Hello, If the memory is 80 Mpts for one channel, it takes (80 Mpts) / (5000 Mpts/s) = 0.016 s. The device only makes the specified 64K wfm/s under certain conditions and this is certainly only the case if the memory used is <= (5000 Mpts/s) / (64000 1/s) = 78125 pts Best regards egonotto |
| ballsystemlord:
--- Quote from: egonotto on May 28, 2024, 04:23:23 am ---Hello, If the memory is 80 Mpts for one channel, it takes (80 Mpts) / (5000 Mpts/s) = 0.016 s. The device only makes the specified 64K wfm/s under certain conditions and this is certainly only the case if the memory used is <= (5000 Mpts/s) / (64000 1/s) = 78125 pts Best regards egonotto --- End quote --- Because there's dead time, doesn't that mean that you can't just divide 80Mpts by 5GS/s? Like, you have to put the 64K-wfm/s into the equation somehow? |
| egonotto:
Hello, there is no dead time in an acquisition. This only exists between the acquisition. Best regards egonotto |
| wraper:
You can really only make assumptions for a single shot capture. "64K wfm/s" doesn't really mean anything, it could easily be only with some obscure combination of settings and 10-100x worse otherwise even if selected time base would let you think otherwise. I actually have an oscilloscope that at fastest time bases dramatically reduces its capture rate to the level of dog shit (even with lowest memory depth) despite being pretty good in the middle :palm:. |
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